# CBSE Class 10-Mathematics: Chapter –14 Statistics Part 1

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**Question 1:**

Marks obtained by students are given below

Marks | |||||||

No. of Students |

**Answer:**

Marks | No. of students | |

The corresponding value of marks for

**Question 2:**

The sum of deviations of a set of values , measured from is and the sum of deviations of the values from is . Find the value of and the mean

**Answer:**

We have

Subtracting (2) from (1), we get

we get

Mean

Hence and mean

**Question 3:**

Prove that

**Answer:**

To prove algebraic sum of deviation from mean is zero

We have,

Now

Hence,

**Question 4:**

Compute the median from the following data

Mid Value | |||||||||

Frequency |

**Answer:**

Here, we are given the mid values. So, we should first find the upper and lower limits of the various classes. The difference between two consecutive values is

Lower limit of a class Midvalue

Upper limit

Calculate of Median

Mid-value | Class Groups | Frequency | Cumulative Frequency |

We have

The cumulative frequency first greater than N i.e. is and the corresponding class is is the median class

Now,

Median

Median