# CBSE Class 10-Mathematics: Chapter –8 Introduction to Trigonometry Part 15

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Question6:

Use Euclid’s division algorithm to find the HCF of:

(i) and

(ii) and

(iii) and

(i) and

We have ,

So, we apply the division lemma to and to obtain

Here remainder , we apply the division lemma again to and to obtain

We consider the new divisor and new remainder , and apply the division lemma to obtain

Since that time, the remainder is zero, the process get stops.

The divisor at this stage is

Therefore, the HCF of and is.

(ii) and

and

We have ,

So, we apply the division lemma to and to obtain

Since we get the remainder is zero, the process stops.

The divisor at this stage is ,

Therefore, HCF of and is .

(iii) and

We have ,

So, we apply the division lemma to and to obtain

Here remainder , we apply the division lemma again to and to obtain

Here remainder , we apply the division lemma again to and to obtain

Since we get the remainder is zero, the process stops.

The divisor at this stage is ,

Therefore, HCF of and is .