NCERT Class 10 Chapter 14 Statistics CBSE Board Sample Problems Very Short Answer (For CBSE, ICSE, IAS, NET, NRA 2022)

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Question

Given below is a cumulative frequency distribution of “less than type” .

Given below is a Cumulative Frequency Distribution of ″ Less Than Type
Marks obtainedLess than 20Less than 30Less than 40Less than 50
No. of students cumulative frequency8131924

Change the above data into a continuous grouped frequency distribution

Solution

Change the Above Data into a Continuous Grouped Frequency Distribution
Class intervalNumber of students ()
10 - 20

20 - 30

30 - 40

40 - 50

8

5

6

5

Question

In a frequency distribution, if a = assumed mean = 55, , h = 10 and , then find the mean of the distribution

Solution

Mean

Question

Find mode using an empirical relation when it is given that mean and median are 10.5 and 9.6 respectively.

Solution

Mean and median

Empirical relation: 3 Median

Mode

Question

A class teacher has the following absentee record of 40 students of a class for the whole term.

Absentee Record of 40 Students of a Class for the Whole Term
No. of days0 - 66 - 1010 - 1414 - 2020 - 2828 - 3838 - 40
No. of students111074431

Write the above distribution as less than type cumulative frequency distribution.

Solution

Less Than Type Cumulative Frequency Distribution
No. of daysLess than 6Less than

10

Less than

14

Less than

20

Less than

28

Less than

38

Less than

40

No. of students11212832363940

Question

Following is a cumulative frequency curve for the marks obtained by 40 students as shown in figure. Find the median marks obtained by the student.

A Cumulative Frequency Curve

Solution

40

Question

In a frequency distribution mode is 7.88, mean is 8.32 find the median.

Solution

Mode = 3 median mean

Median

median

= median

Median = 8.17

Question

The class in which mode lies is called as

Solution

Modal class

Question

If mean = 31.04 and median = 30.625, then find the mode.

Solution

3median mode + 2 mean

Mode

Mode

Question

The mean and median of a distribution are both equal to 635.97. Find the mode

Solution

Mode = 635.97