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NCERT Class 10 Chapter 14 Statistics CBSE Board Sample Problems Very Short Answer
Question
Given below is a cumulative frequency distribution of “less than type” .
Marks obtained | Less than 20 | Less than 30 | Less than 40 | Less than 50 |
No. of students cumulative frequency | 8 | 13 | 19 | 24 |
Change the above data into a continuous grouped frequency distribution
Solution
Class interval | Number of students () |
10 - 20 20 - 30 30 - 40 40 - 50 | 8 5 6 5 |
Question
In a frequency distribution, if a = assumed mean = 55, , h = 10 and , then find the mean of the distribution
Solution
Mean
Question
Find mode using an empirical relation when it is given that mean and median are 10.5 and 9.6 respectively.
Solution
Mean and median
Empirical relation: 3 Median
Mode
Question
A class teacher has the following absentee record of 40 students of a class for the whole term.
No. of days | 0 - 6 | 6 - 10 | 10 - 14 | 14 - 20 | 20 - 28 | 28 - 38 | 38 - 40 |
No. of students | 11 | 10 | 7 | 4 | 4 | 3 | 1 |
Write the above distribution as less than type cumulative frequency distribution.
Solution
No. of days | Less than 6 | Less than 10 | Less than 14 | Less than 20 | Less than 28 | Less than 38 | Less than 40 |
No. of students | 11 | 21 | 28 | 32 | 36 | 39 | 40 |
Question
Following is a cumulative frequency curve for the marks obtained by 40 students as shown in figure. Find the median marks obtained by the student.
Solution
40
Question
In a frequency distribution mode is 7.88, mean is 8.32 find the median.
Solution
Mode = 3 median mean
Median
median
= median
Median = 8.17
Question
The class in which mode lies is called as
Solution
Modal class
Question
If mean = 31.04 and median = 30.625, then find the mode.
Solution
3median mode + 2 mean
Mode
Mode
Question
The mean and median of a distribution are both equal to 635.97. Find the mode
Solution
Mode = 635.97