# NCERT Class 10 Chapter 3 Arithmetic Progressions Official CBSE Board Sample Problems Long Answer (For CBSE, ICSE, IAS, NET, NRA 2022)

Glide to success with Doorsteptutor material for CBSE : fully solved questions with step-by-step explanation- practice your way to success.

## Question

**Divide 56 in four parts in A. P such that the ratio of the product of their extremes (1 ^{st} and 4^{th} ) to the product of means (2^{nd} and 3^{rd}) is 5: 6**.

### Solution

Let the four parts of the A. P. are

*Now*, *[* Sum = 56]

According to question,

Thus, 4 parts are .

## Question

**The sums of first n terms of three arithmetic progressions are** **and** **respectively**.

**The first term of each AR is 1 and their common differences are 1,2 and 3 respectively**.

Prove that

### Solution

Here, sum of *n* terms of AP is

[ where ]

[ where ]

Here, sum of n terms of AP is

[ where ]

[ where ]

Here, sum of n terms of AP is

[ where ]

[ where ]

Here, sum of *n* terms of AP is

[ where ]

[ Where ]

Here, sum of n terms of AP is

[ Where

[ Where

Now, consider

## Question

**The digits of a positive number of three digits are in A. P. and their sum is 15. The number obtained by reversing the digits is 594 less than the original number. Find the number**.

### Solution

Let the required numbers in AR arc respectively.

Now, ( Sum of digits )

According to question, number is

, i.e..

Number on reversing the digits is

i.e..

Now, as per given condition in question,

Digits of number arc

Required number is

## Question

**If the ratio of the sum of first n terms of two A. P. ā² s is**, **find the ratio of their mth terms**.

### Solution

*ā¦ (i)*

*Since*

So replacing by , i.e.. in (i)

Thus, the ratio of their mth terms is

## Question

**If the sum of first 7 terms of an A. P. is 49 and that of its first 17 terms is 289, find the sum of first n terms of the A. P**

### Solution

Given:

, where

ā¦ (i)

Similarly,

ā¦ *(ii)*

Solving (1) and (ii) , we get

and

## Question

**The sum of first 9 terms of an AP is 81 and the sum of its first 20 terms is 400. Find the first term and the common difference of the AP**.

### Solution

Solving the two equations we get

and

## Question

**513 logs are stacked in the following manner; 54 logs at the bottom row, 51 in the next row, 48 in the row next to it and so on. In how many rows are the 513 logs placed and how many logs are in the top row?**

### Solution

Number of rows = 18

Number of logs in top row

## Question

**The sum of four consecutive numbers in an AP is 32 and the ratio of the product of the first and the last term to the product of two middle terms is 7: 15. Find the numbers**.

### Solution

Let the four numbers in AP be a

Numbers are 2, 6,10, 14 (when ) and 14,10, 16 and

## Question

**If the sum of m terms of an AP is the same as the sum of its n terms, show that the sum of its** **terms is zero**.

### Solution

*Let first term of A. P. be āaā and common difference be ādā* .

*Sum of* *terms*

Hence sum of terms is zero

## Question

**How many terms of the AP 24,21, 18 ā¦ Must be taken so that the sum is 78? Explain the double answer**.

### Solution

First term,

Common difference.

Let the number of terms to get sum 78 is n.

Solving the quadratic equation, we get and .

So you can take either 4 terms or 13 terms to get the sum 78.

The reason for the double answer is that the sum of terms from 5^{th} to 13^{th} is zero as some terms are positive and some terms are negative.