NCERT Class 11 Mathematics Solutions: Chapter 11 – Conic Sections Miscellaneous Exercise 11 Part 3 (For CBSE, ICSE, IAS, NET, NRA 2022)

Glide to success with Doorsteptutor material for CBSE/Class-7 : get questions, notes, tests, video lectures and more- for all subjects of CBSE/Class-7.

In Figure Formula of Ellipse is Given

1. An arch is in the form of a semi-ellipse. It is wide and high at the centre. Find the height of the arch at a point from one end.


Since the height and width of the arc from the centre is and 8 m respectively, it is clear that the length of the major axis is , while the length of the semi-minor axis is .

The origin of the coordinate plane is taken as the centre of the ellipse, while the major axis is taken along the x-axis. Hence, the semi-ellipse can be diagrammatically represented as:

The Centre of the Ellipse

The equation of the semi-ellipse will be of the form where is the semi-major axis.


So, the equation of the semi-ellipse is


Consider be a point on the major axis such that .

Draw .

The x-coordinate of point is

On substituting the value of with in equation (1)


So, the height of the arch at a point 1 from one end is approximately

2. A rod of length moves with its ends always touching the coordinate axes. Determine the equation of the locus of a point on the rod, which is from the end in contact with the axis.


Consider be the rod making an angle with be the point on it such that .


From , draw .

AB be the Rod Making an Angle (Theta) with OX and P (X, Y)




So, the equation of the locus of point on the rod is

Developed by: