CBSE Class 11-Physics: Momentum Conservation Equation Tutorial-II
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How to Solve Momentum Conservation Equation
Law of conservation for isolated system
First read the problem and understand the quantities given
Choose a suitable system where law of conservation of momentum can be applied.
It can be for certain time duration also.
Importance should be given to this step
Choose a suitable Coordinate system and write down the momentum equation in XYZ axes.
Note we need to add all the object in the system in the momentum equation and find the unknown
In case of collisions, if the collision is elastic, apply kinetic energy conservation also
Question:
bullet is fired horizontally with the speed into a. block of wood at rest on the table.
The bullet lodges into the block. If the coefficient of friction between the block and the table is.
a) What is the velocity of block after the bullet is lodges into the block
b) How far will the block slide.
c)How much energy is lost by the bullet in collision
d) How much energy is dissipated in friction.
Solution:
First, we need to understand the problem and find out the known and unknown. Initial momentum of bullet is known
Here first collision happens and then bullet, and block system moves, and friction opposes the option and they come to rest
Choose the suitable system. Here Bullet and block can be taken as the system. So, in collision Law of conservation can be applied. After the collision, we can use Work and energy method
Since this is one dimensional collision. we just need to consider everything in one axis
So, applying law of conservation for the collision part
Initial momentum ,
Final momentum
Now initial momentum=final momentum
.
This cover the answer (a)
Solution continued….
Now the frictional force acting will be
Now from work kinetic energy equation we know that
Or
Now energy lost by bullet in collision
energy of bullet Final energy of block bullet system after the collision
Answer is C
So, energy dissipated in friction
Answer is D