CBSE Class 11-Physics: Thermodynamics Problem's: Questions

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Question:

One mole of an ideal monoatomic gas is taken round the cyclic process ABCDA as shown in figure.

A) Work done by the gas

b. Heat absorbed by the gas in AB and BC

c. Heat in process CD

d. Find the temperature at C and D

e. Maximum temperature attained by the gas during the cycle

f. Net change in the internal energy and the heat

Net change in the internal energy and the heat

Net Change in the Internal Energy and the Heat

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Solution:

For monoatomic gas

a) Work done by the gas Area enclosed by the curve

Work done by the gas

Work Done by the Gas

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Solution continued:

Heat absorbed the gas in

Heat absorbed the gas in BC

Heat absorbed the gas in BC

Heat Absorbed the Gas in BC

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Solution continued

Heat rejected in DA

Now for the cycle process

So,

Now for the cycle process

Now for the Cycle Process

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Solution continued:

From diagram and

From diagram and PV=RT

From Diagram and PV=RT

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Solution Continued:

Max temperature will be on the slope CD

Equation of Slope CD as Coordinated system

Taking the values for C and D, we get

Now

So,

For max

should be zero

So

Net heat

From diagram and PV=RT

From Diagram and PV=RT

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Max temperature will be on the slope CD