# NCERT Class 12-Mathematics: Chapter – 12 Linear Programming Part 2 (For CBSE, ICSE, IAS, NET, NRA 2022)

Glide to success with Doorsteptutor material for CBSE/Class-12 : get questions, notes, tests, video lectures and more- for all subjects of CBSE/Class-12.

**Question 2**:

Determine the minimum value of (if any) , if the feasible region for an LPP is shown in Fig. 12.2.

**Answer**:

The feasible region (R) is unbounded. Therefore minimum of Z may or may not exist. If it exists, it will be at the corner point (Fig. 12.2) .

Corner Point | Value of Z |

Let us graph . We see that the open half plane determined by and R do not have a common point. So, the smallest value is the minimum value of Z.

**Question 3**:

Solve the following LPP graphically:

Maximise , subject to

**Answer**:

The shaded region in the Fig. 12.3 is the feasible region determined by the system of constraints and .

The feasible region OAB is bounded, so, maximum value will occur at a corner point of the feasible region.

Corner Points are and .

Evaluate Z at each of these corner point.

Corner Point | Value of Z |

Hence, the maximum value of Z is 12 at the point

**Question 4**:

A manufacturing company makes two types of television sets; one is black and white and the other is colour. The company has resources to make at most 300 sets a week. It takes ₹ 1800 to make a black and white set and to make a coloured set. The company can spend not more than a week to make television sets. If it makes a profit of ₹ 510 per black and white set and per coloured set, how many sets of each type should be produced so that the company has maximum profit? Formulate this problem as a LPP given that the objective is to maximise the profit.

**Answer**:

Let *x* and *y* denote, respectively, the number of black and white sets and coloured sets made each week. Thus

Since the company can make at most sets a week, therefore,

Weekly cost (in ₹) of manufacturing the set is

and the company can spend upto . Therefore,

The total profit on *x* black and white sets and *y* colour sets is . This is the objective function.

Thus, the mathematical formulation of the problem is

Maximise

subject to the constraints: