NCERT Mathematics Class 9 Exemplar Ch 9 Areas of Parallelograms and Triangles Part 5

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Exercise 9.3

Q.1. In Fig, PSDA is a parallelogram. Points Q and R are taken on PS such that and . Prove that

PSDA is a parallelogram

PSDA is a Parallelogram

PSDA is a parallelogram

Q.2. X and Y are points on the side LN of the triangle LMN such that Through X, a line is drawn parallel to LM to meet MN at Z (See Fig.). Prove that ar

X and Y are points on the side LN of the triangle LMN

X and Y Are Points on the Side LN of the Triangle LMN

X and Y are points on the side LN of the triangle LMN

Q.3. The area of the parallelogram ABCD is (see Fig.). Find

(i) ar (ABEF)

(ii) ar (ABD)

(iii) ar (BEF)

The area of the parallelogram ABCD is 90 cm2

The Area of the Parallelogram ABCD is 90 cm2

The area of the parallelogram ABCD is 90 cm2

Answer: (i)

(ii)

(iii)

Q.4. In ∆ ABC, D is the mid-point of AB and P is any point on BC. If meets AB in Q (Fig), then prove that ar

The mid-point of AB and P is any point on BC

The Mid-Point of AB and P is Any Point on BC

The mid-point of AB and P is any point on BC

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