NCERT Physics Class 12 Exemplar Ch 12 Atoms Part 2
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Short Answer
19 Positronium is just like a Hatom with the proton replaced by the positively charged antiparticle of the electron (called the positron which is as massive as the electron). What would be the ground state energy of Positronium?
Ans:
The ‘m’ that occurs in the Bohr formula is the reduced mass. For Hatom, For Positronium. Hence for a Positronium
20 Assume that there is no repulsive force between the electrons in an atom but the force between positive and negative charges is given by Coulomb’s law as usual. Under such circumstances, calculate the ground state energy of a Heatom.
Ans:

For a nucleus with charge 2e and electrons of charge –e, the levels are .

The ground state will have two electrons each of energy E, and the total ground state energy would by
21 Using Bohr model, calculate the electric current created by the electron when the Hatom is in the ground state.
Ans:
velocity of electron
Bohr radius.
Number of revolutions per unit time
22 Show that the first few frequencies of light that is emitted when electrons fall to the level from levels higher than, are approximate harmonics (i.e. in the ratio 1: 2: 3...) when.
Ans:
Where and R is Rydberg constant.
For
Thus, are approximately in the order
23 What is the minimum energy that must be given to a H atom in ground state so that it can emit an line in Balmer series. If the angular momentum of the system is conserved, what would be the angular momentum of such photon?
Ans:

in Balmer series corresponds to transition to . So the electron in ground state n = 1 must first be put in state.

Energy required.

If angular momentum is conserved, angular momentum of photon = change in angular momentum of electron