NEET (2024 Updated)-National Eligibility cum Entrance Test (Medical) Chemistry Coaching Programs

πŸ“Ή Video Course 2024 (8 Lectures [4 Hrs : 33 Mins]): Offline Support

Click Here to View & Get Complete Material

Rs. 100.00

1 Month Validity (Multiple Devices)

⏳ 🎯 Online Tests (5 Tests [50 Questions Each]): NTA Pattern, Analytics & Explanations

Click Here to View & Get Complete Material

Rs. 500.00

3 Year Validity (Multiple Devices)

πŸŽ“ Study Material (159 Notes): 2024-2025 Syllabus

Click Here to View & Get Complete Material

Rs. 350.00

3 Year Validity (Multiple Devices)

🎯 3111 MCQs (& PYQs) with Full Explanations (2024-2025 Exam)

Click Here to View & Get Complete Material

Rs. 650.00

3 Year Validity (Multiple Devices)

NCERT Class - 9 Science Solutions: Chapter 8 - Motion Part 5

Question 20:

An object starting from rest travels in first and in next . What will be the velocity after from the start?

Answer:

Since acceleration is the same, we have

Question 21:

Using following data, draw time - displacement graph for a moving object:

Time vs displacementTime vs Displacement
Time (s)0246810121416
Displacement (m)024446420

Use this graph to find average velocity for first , for next and for last .

Answer:

Illustration: NCERT Class - 9 Science Solutions: Chapter 8 - Motion Part 5

Average velocity for first 4 s.

For next 4 s

(or as x remains the same from 4 to 8 seconds, velocity is zero)

For last 6 s

Question 22:

An electron moving with a velocity of enters into a uniform electric field and acquires a uniform acceleration of in the direction of its initial motion.

  1. Calculate the time in which the electron would acquire a velocity double of its initial velocity.
  2. How much distance the electron would cover in this time?

Answer:

Given initial velocity

And acceleration

  1. Final velocity

    To find

  2. Using