Chemistry Class 11 NCERT Solutions: Chapter 1 Some Basic Concepts of Chemistry Part 2

Q: 3 Determine the empirical formula of an oxide of iron which has 69.9% iron and 30.1% Dioxygen by mass.

This structure is react with oxygen to oxide and iron reacts with oxygen to iron oxide

Structure of Balancing Chemical Reactions

This structure is react with oxygen to oxide and iron reacts with oxygen to iron oxide

Answer:

% of iron by mass = 69.9 % [Given]

% of oxygen by mass = 30.1 % [Given]

Relative moles of iron in iron oxide:

Equation

Equation

Equation

Relative moles of oxygen in iron oxide:

Equation

Equation

Equation

Simplest molar ratio of iron to oxygen:

Equation

Equation

Equation

Equation

Q: 4 calculate the amount of carbon dioxide that could be produced when

This structure is 0.5moles of carbon will produce 0.5 moles of carbon dioxide

Structure of Carbon Dioxide

This structure is 0.5moles of carbon will produce 0.5 moles of carbon dioxide

(i) 1 mole of carbon is burnt in air.

(ii) 1 mole of carbon is burnt in 16 g of Dioxygen.

(iii) 2 moles of carbon are burnt in 16 g of Dioxygen

Answer:

The balanced reaction of combustion of carbon can be written as:

(i) As per the balanced equation, 1 mole of carbon burns in 1 mole of Dioxygen (air) to produce 1 mole of carbon dioxide.

(ii) According to the question, only 16 g of Dioxygen is available. Hence, it will react with Equation mole of carbon to give 22 g of carbon dioxide. Hence, it is a limiting reactant.

(iii) According to the question, only 16 g of Dioxygen is available. It is a limiting reactant. Thus, 16 g of Dioxygen can combine with only 0.5 mole of carbon to give 22 g of carbon dioxide.

Q: 5. Calculate the mass of sodium acetate Equation required to make 500 mL of 0.375 molar aqueous solutions. Molar mass of sodium acetate is Equation

This structure is Number of moles of sodium acetate in 500 ml

Structure of Sodium Acetate(CH3COONa)

This structure is Number of moles of sodium acetate in 500 ml

Answer:

0.375 M aqueous solution of sodium acetate

Equation mL of solution containing 0.375 moles of sodium acetate

∴Number of moles of sodium acetate in 500 mL

Equation

Equation mole

Molar mass of sodium acetate Equation

Equation

Equation

Q: 6 Calculate the concentration of nitric acid in moles per litre in a sample which has a density, Equation and the mass per cent of nitric acid in it being Equation

Answer:

Mass percent of nitric acid in the sample Equation

Thus, 100 Equation of nitric acid contains Equation of nitric acid by mass.

Molar mass of nitric acid Equation

This structure is 100g of nitric acid contains 69g of nitric acid by mass

Structure of Nitric Acid HNO3

This structure is 100g of nitric acid contains 69g of nitric acid by mass

Equation

Equation

Equation

∴ Number of moles in Equation

Equation

Equation

Volume of Equation of nitric acid solution

Equation

Equation

Equation

Concentration of nitric acid

Equation

Equation

∴ Concentration of nitric acid Equation

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