Chemistry Class 11 NCERT Solutions: Chapter 12 Organic Chemistry Some Basic Principles and Techniques Part 15

Q: 32. An organic compound contains Equation carbon and Equation hydrogen, the remainder being oxygen. Calculate the masses of carbon dioxide and water produced when Equation of this substance is subjected to complete combustion.

Answer:

Percentage of carbon in organic compound Equation

That is, Equation of organic compound contains Equation of carbon.

Equation of organic compound will contain Equation

Molecular mass of carbon dioxide, Equation

That is, Equation of carbon is contained in Equation of Equation

Therefore, Equation of carbon will be contained in Equation

Thus, Equation will be produced on complete combustion of Equation of organic compound.

Percentage of hydrogen in organic compound is Equation

i.e., Equation of organic compound contains Equation of hydrogen.

Therefore, Equation of organic compound will contain Equation

It is known that molecular mass of water Equation is Equation .

Thus, Equation of hydrogen is contained in Equation of water.

Equation of water

Thus, Equation of water will be produced on complete combustion of Equation of the organic compound.

Q: 33. A sample of Equation of an organic compound was treated according to Kjeldahl’s method. The ammonia evolved was absorbed in Equation of 0.5 M Equation . The residual acid required Equation of Equation solution of Equation for neutralisation. Find the percentage composition of nitrogen in the compound.

Answer:

Given that, total mass of organic compound Equation

Equation mL of Equation M solution of Equation was required by residual acid for neutralisation.

Equation mL of Equation M Equation solution Equation Equation

∴Acid consumed in absorption of evolved ammonia is Equation

Again, Equation

Also, since 1000 mL of 1 MNH3 contains 14 g of nitrogen,

Equation will contain Equation

Therefore, percentage of nitrogen in Equation of organic compound Equation Equation

Q: 34. Equation of an organic chloro compound gave Equation of silver chloride in Carius estimation. Calculate the percentage of chlorine present in the compound.

Answer:

Given that

Mass of organic compound is Equation

Mass of Equation formed Equation

1 mol of Equation contains Equation of Equation .

Thus, mass of chlorine in Equation of Equation

Equation

Equation

∴ Percentage of chlorine Equation Equation

Hence, the percentage of chlorine present in the given organic chloro compound is Equation .

Q: 35. In the estimation of sulphur by Carius method, Equation of an organic sulphur compound afforded Equation of barium sulphate. Find out the percentage of sulphur in the given compound.

Answer:

Total mass of organic compound Equation

Mass of barium sulphate formed Equation

Equation

Thus, Equation of Equation contains Equation of sulphur Equation g of sulphur

Therefore, percentage of sulphur Equation

Hence, the percentage of sulphur in the given compound is Equation .

Q: 36. In the organic compound Equation , the pair of hybridised orbitals involved in the formation of: Equation bond is:

(A) Equation

(B) Equation

(C) Equation

(D) Equation

Answer:

Equation

In the given organic compound, the carbon atoms numbered as Equation and Equation are Equation , and Equation hybridized respectively. Thus, the pair of hybridized orbitals involved in the formation of Equation bond is sp Equation .

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