Chemistry Class 11 NCERT Solutions: Chapter 2 Structure of Atom Part 11

Q: 35. If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms, which can be placed side by side in a straight line across length of scale of length 20 cm long.

Answer:

Equation

Equation

Length of the scale Equation

Equation

Diameter of a carbon atom =0.15 nm

Equation

One carbon atom occupies Equation

Equation

Equation

Equation

Equation

Q: 36. Equation atoms of carbon are arranged side by side. Calculate the radius of carbon atom if the length of this arrangement is 2.4 cm.

Answer:

Length of the given arrangement = 2.4 cm

Number of carbon atoms present = Equation

Equation

Equation

Equation

Equation

Equation

Equation

Q: 37 The diameter of zinc atom is Equation . Calculate (a) radius of zinc atom in pm and (b) number of atoms present in a length of Equation if the zinc atoms are arranged side by side lengthwise.

Answer:

(a) Radius of zinc atom Equation

Equation

Equation

Equation

(b) Length of the arrangement Equation

Equation

Diameter of zinc atom Equation

Equation

Equation

Equation

Equation

Q: 38 A certain particle carries Equation of static electric charge. Calculate the number of electrons present in it.

Answer:

Charge on one electron Equation

Equation Charge is carried by Equation electron.

Equation

Equation

Equation

Equation

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