Chemistry Class 11 NCERT Solutions: Chapter 2 Structure of Atom Part 11
Q: 35. If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms, which can be placed side by side in a straight line across length of scale of length 20 cm long.
Length of the scale
Diameter of a carbon atom =0.15 nm
One carbon atom occupies
Q: 36. atoms of carbon are arranged side by side. Calculate the radius of carbon atom if the length of this arrangement is 2.4 cm.
Length of the given arrangement = 2.4 cm
Number of carbon atoms present =
Q: 37 The diameter of zinc atom is . Calculate (a) radius of zinc atom in pm and (b) number of atoms present in a length of if the zinc atoms are arranged side by side lengthwise.
(a) Radius of zinc atom
(b) Length of the arrangement
Diameter of zinc atom
Q: 38 A certain particle carries of static electric charge. Calculate the number of electrons present in it.
Charge on one electron
Charge is carried by electron.