Chemistry Class 11 NCERT Solutions: Chapter 2 Structure of Atom Part 11

Q: 35. If the diameter of a carbon atom is 0.15 nm, calculate the number of carbon atoms, which can be placed side by side in a straight line across length of scale of length 20 cm long.

Image of Carbon Atom for Structure in Atom

Image of Carbon Atom

Image of Carbon Atom for Structure in Atom

Answer:

Equation

Equation

Length of the scale Equation

Equation

Diameter of a carbon atom =0.15 nm

Equation

One carbon atom occupies Equation

Equation

Equation

Equation

Equation

Q: 36. Equation atoms of carbon are arranged side by side. Calculate the radius of carbon atom if the length of this arrangement is 2.4 cm.

Answer:

Length of the given arrangement = 2.4 cm

Number of carbon atoms present = Equation

Equation

Equation

Equation

Equation

Equation

Equation

Q: 37 The diameter of zinc atom is Equation . Calculate (a) radius of zinc atom in pm and (b) number of atoms present in a length of Equation if the zinc atoms are arranged side by side lengthwise.

Image of Zinc's for Structure in Atom

Image of Zinc's

Image of Zinc's for Structure in Atom

Answer:

(a) Radius of zinc atom Equation

Equation

Equation

Equation

(b) Length of the arrangement Equation

Equation

Diameter of zinc atom Equation

Equation

Equation

Equation

Equation

Q: 38 A certain particle carries Equation of static electric charge. Calculate the number of electrons present in it.

Image of Electrons for Structure in Atom

Image of Electrons

Image of Electrons for Structure in Atom

Answer:

Charge on one electron Equation

Equation Charge is carried by Equation electron.

Equation

Equation

Equation

Equation

Explore Solutions for Chemistry

Sign In