(a) The threshold wavelength and
(b) The threshold frequency of the radiation
If the caesium element is irradiated with a wavelength 500 nm, calculate the kinetic energy and the velocity of the ejected photoelectron.
Answer: This is given that the work function
(a) From the expression, , we get:
Substituting the values in the given expression of
Hence, the threshold wavelength is 653 nm.
(b) From the expression, we get:
H = Planck’s constant
Substituting the values in the given expression of:
Hence, the threshold frequency of radiation
(c) According to the question:
Wavelength used in irradiation
Kinetic energy of the ejected photoelectron
Hence, the velocity of the ejected photoelectron (v) is