Chemistry Class 11 NCERT Solutions: Chapter 2 Structure of Atom Part 3

Q: 6. Find energy of each of the photons which

Image of Energy of a Photon for Structure of Atom

Image of Energy of a Photon

Image of Energy of a Photon for Structure of Atom

(i) Correspond to light of frequency Equation

(ii) Have wavelength of Equation

Answer:

(i) Energy (E) of a photon is given by the expression,

Equation

Where,

Equation

Equation = frequency of light Equation

Substituting the values in the given expression Equation

Equation

Equation

(ii) Energy (E) of a photon having wavelength (λ)is given by the expression,

Equation

Equation

Equation

Substituting the values in the given expression of E:

Equation

Equation

Q: 7. Calculate the wavelength, frequency and wave number of a light wave whose period is Equation .

Image of Wavelength and Frequency for Structure of Atom

Image of Wavelength and Frequency

Image of Wavelength and Frequency for Structure of Atom

Answer:

Equation

Equation

Wavelength ( Equation ) of light Equation

Where,

Equation

Substituting the value in the given expression of Equation

Equation

Wave number Equation

Q: 8. What is the number of photons of light with a wavelength of 4000 pm that provide 1 J of energy?

Image of Light of Wavelengths for Structure of Atom

Image of Light of Wavelengths

Image of Light of Wavelengths for Structure of Atom

Answer;

Equation

Equation

Equation

Where,

Equation wavelength of light Equation

Equation

Equation

Substituting the values in the given expression of n:

Equation

Hence, the number of photons with a wavelength of 4000 pm and energy of Equation photons.

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