Chemistry Class 11 NCERT Solutions: Chapter 6 Thermodynamics Part 3

Q: 11 Enthalpy of combustion of carbon to Equation is Equation Calculate the heat released upon formation of Equation of Equation from carbon and dioxygen gas.

Answer:

Formation of Equation from carbon and dioxygen gas can be represented as:

Equation

Equation

Heat released on formation of Equation

Equation

Equation

Equation

Q: 12. Enthalpies of formation of Equation

Equation respectively. Find the value of Equation for the reaction: Equation

Answer:

Equation for a reaction is defined as the Equation difference between Equation value of products and Equation value of reactants.

Equation

For the given reaction,

Equation

Equation

Substituting the values of Equation question, we get:

Equation

Equation

Hence, the value of Equation for the reaction is Equation

Q: 13 Given

Equation

What is the standard enthalpy of formation of Equation gas?

Answer:

Standard enthalpy of formation of a compound is the change in enthalpy that takes place during the formation of 1 mole of a substance in its standard form its constituent elements in their standard state.

Re-Writing the given equation for 1 mole of Equation

Equation

Equation

Equation Equation

Equation Equation

Equation

Q: 14. Calculate the standard enthalpy of formation of Equation from following data:

Equation

Equation

Equation

Answer:

The reaction that takes place during the formation of Equation can be written as:

Equation

The reaction (1) can be obtained from the given reactions by following the algebraic calculations as:

Equation (ii) Equation equation (iii) – equation (i)

Equation

Equation

Equation

Equation

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