Chemistry Class 11 NCERT Solutions: Chapter 6 Thermodynamics Part 5

Q: 20. The equilibrium constant is 10. What will be the value of Equation

Answer:

From the expression,

Equation

Equation

Equation

Equation

Equation

Q: 21. Comment on the thermodynamic stability of Equation given

Equation

Equation

Answer:

The positive value of Equation indicates that heat is absorbed during the formation of Equation

This means that Equation has higher energy than the reactants Equation Hence, Equation is unstable.

The negative value of Equation indicates that heat is evolved during the formation of Equation from Equation The product, Equation is stabilized with minimum energy.

Hence, unstable Equation changes to unstable Equation

Q: 22. Calculate the entropy change in surroundings when 1.00 mol of Equation is formed under standard conditions. Equation

Answer:

It is given that 286 kJ Equation of heat is evolved on the formation of Equation Thus, Equation

Entropy change Equation for the surroundings = Equation

Equation

Equation

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