Chemistry Class 11 NCERT Solutions: Chapter 6 Thermodynamics Part 5

Download PDF of This Page (Size: 231K)

Q: 20. The equilibrium constant is 10. What will be the value of


From the expression,

Q: 21. Comment on the thermodynamic stability of given


The positive value of indicates that heat is absorbed during the formation of

This means that has higher energy than the reactants Hence, is unstable.

The negative value of indicates that heat is evolved during the formation of from The product, is stabilized with minimum energy.

Hence, unstable changes to unstable

Q: 22. Calculate the entropy change in surroundings when 1.00 mol of is formed under standard conditions.


It is given that 286 kJ of heat is evolved on the formation of Thus,

Entropy change for the surroundings =