Chemistry Class 11 NCERT Solutions: Chapter 6 Thermodynamics Part 5 (For CBSE, ICSE, IAS, NET, NRA 2022)

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Q: 20. The equilibrium constant is 10. What will be the value of

Energy and Equilibrium for Thermodynamics

Answer:

From the expression,

Q: 21. Comment on the thermodynamic stability of given

Answer:

The positive value of indicates that heat is absorbed during the formation of

This means that has higher energy than the reactants Hence, is unstable.

The negative value of indicates that heat is evolved during the formation of from The product, is stabilized with minimum energy.

Hence, unstable changes to unstable

O2 and NO2 for Thermodynamics

Q: 22. Calculate the entropy change in surroundings when 1.00 mol of is formed under standard conditions.

Entropy for Thermodynamics

Answer:

It is given that 286 kJ of heat is evolved on the formation of Thus,

Entropy change for the surroundings =

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