Chemistry Class 11 NCERT Solutions: Chapter 7 Equilibrium Part 10

Download PDF of This Page (Size: 352K)

Chemistry Class 11 NCERT Solutions Chapter 7 Equilibrium Part 10

Q: 27. Find the equilibrium constant for the following reaction is at

Structure of Bond Energy for Hydrogen, Chlorine

Structure of Bond Energy for Hydrogen, Chlorine

Structure of Bond Energy for Hydrogen, Chlorine

Find the equilibrium pressure of all gases if 10.0 bar of is introduced into a sealed container at 1024 K.

Answer: Given,

Therefore, for the reaction the equilibrium constant will be,

Now, let p be the pressure of both H2 and at equilibrium.

Now, we can write,

Therefore, at equilibrium,

Q: 28. Dihydrogen gas is obtained from natural gas by partial oxidation with steam as per following endothermic reaction:

Image of Transition Temperature

Image of Transition Temperature

Image of Transition Temperature

(A) Write as expression for for the above reaction.

(B) How will the values of

(i) Increasing the pressure

(ii) Increasing the temperature

(iii) Using a catalyst?

Answer:

(A) For the given reaction,

(B) (i) According to Le chatelier’s principle, the equilibrium will shift in the backward direction

(ii) According to Le Chatelier’s principle, as the reaction is endothermic, the equilibrium will shift in the forward direction

(iii) The equilibrium of the reaction is not affected by the presence of a catalyst. A catalyst only increases the rate of a reaction. Thus equilibrium will be attained quickly.

Q: 29. Describe the effect of

(A) Addition of

(B) Addition of

(C) Removal of

(D) Removal of

On the equilibrium of the reaction

Answer:

(A) According to Le Chatelier’s Principle, on addition of the equilibrium of the given reaction will shift in the forward direction

(B) On addition of the equilibrium will shift in the backward direction

(C) On removing equilibrium will shift in the backward direction

(D) On removing , the equilibrium will shift in the forward direction