Chemistry Class 11 NCERT Solutions: Chapter 7 Equilibrium Part 13

Q: 40. Classify the following species into Lewis acids and Lewis bases and show how these act as Lewis acid/base:

(A) Equation

(B) Equation

(C) Equation

(D) Equation

Answer:

(A) Equation is a Lewis base since it can donate its lone pair of electrons

(B) Equation is a Lewis base since it can donate a pair of electrons

(C) Equation is a Lewis acid since it can accept a pair of electrons’

(D) Equation is a Lewis acid since it can accept a pair of electrons

Q: 41. The concentration of hydrogen ion in a sample of soft drink is Equation . What is its Equation ?

Answer: Given,

Equation

Equation Value of soft drink

Equation

Equation

Equation

Equation

Equation

Equation

Q: 42. The pH of a sample of vinegar is 3.76. Calculate the concentration of hydrogen ion in it.

Answer:

Given,

Equation

It is known that,

Equation

Equation

Equation

Equation

Equation

Hence, the concentration of hydrogen ion in the given sample of vinegar is Equation M.

Q: 43. The ionization constant of Equation and Equation respectively. Calculate the ionization constants of the corresponding conjugate base.

Answer:

It is known that,

Equation

Given,

Equation

Hence, Equation of its conjugate base Equation

Equation

Equation

Equation

Given,

Equation

Hence, Equation of its conjugate base Equation

Equation

Equation

Equation

Given,

Equation

Hence, Equation of its conjugate base Equation

Equation

Equation

Equation

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