Chemistry Class 11 NCERT Solutions: Chapter 7 Equilibrium Part 15

Chemistry Class 11 NCERT Solutions Chapter 7 Equilibrium Part 15

Q: 46. The ionization constant of acetic acid is Equation Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ion in the solution and its pH.

Structure of Ionization Constant of Acetic Acid

Structure of Ionization Constant of Acetic Acid

Structure of Ionization Constant of Acetic Acid

Answer:

Method 1

(1) Equation

(2) Equation

Since Equation :

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Method 2

Degree of dissociation,

Equation

Equation

Then, Equation

Equation

Equation

Equation

Equation

Thus, concentration of Equation

Equation

Equation

Equation

Since Equation

Equation

Equation

Equation

Equation

Hence, the concentration of acetate ion in the solution is 0.00093 M and its pH is Equation .

Q: 47. It has been found that the pH of a 0.01M solution of an organic acid is Equation . Calculate the concentration of the anion, the ionization constant of the acid and its Equation

Answer:

Let the organic acid be HA.

Equation

Concentration of HA = 0.01 M

Equation

Equation

Equation

Equation

Then,

Equation

Equation

Equation

Equation

Equation

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