Chemistry Class 11 NCERT Solutions: Chapter 7 Equilibrium Part 15

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Chemistry Class 11 NCERT Solutions Chapter 7 Equilibrium Part 15

Q: 46. The ionization constant of acetic acid is Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ion in the solution and its pH.

Structure of Ionization Constant of Acetic Acid

Structure of Ionization Constant of Acetic Acid

Structure of Ionization Constant of Acetic Acid

Answer:

Method 1

(1)

(2)

Since :

Method 2

Degree of dissociation,

Then,

Thus, concentration of

Since

Hence, the concentration of acetate ion in the solution is 0.00093 M and its pH is .

Q: 47. It has been found that the pH of a 0.01M solution of an organic acid is . Calculate the concentration of the anion, the ionization constant of the acid and its

Answer:

Let the organic acid be HA.

Concentration of HA = 0.01 M

Then,

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