JEE (Based on NTA Guidelines-IIT Engg.) Mains Chemistry Coaching Programs
πΉ Video Course 2024 (0 Lectures [0 Mins]): Offline Support
Click Here to View & Get Complete Material
Rs. 100.00
1 Month Validity (Multiple Devices)
β³ π― Online Tests (1 Tests [30 Questions Each]): NTA Pattern, Analytics & Explanations
Click Here to View & Get Complete Material
Rs. 100.00
3 Year Validity (Multiple Devices)
π Study Material (159 Notes): 2024-2025 Syllabus
Click Here to View & Get Complete Material
Rs. 350.00
3 Year Validity (Multiple Devices)
π― 144 Numeric, 2994 MCQs (& PYQs) with Full Explanations (2024-2025 Exam)
Click Here to View & Get Complete Material
Rs. 650.00
3 Year Validity (Multiple Devices)
Chemistry Class 11 NCERT Solutions: Chapter 7 Equilibrium Part 17
Q: 45. The first ionization constant of is . Calculate the concentration of ion in its 0.1 M solution. How this concentration be affected if the solution is 0.1 M in HCl also? If the second dissociation constant of is calculate the concentration of under both conditions.
Answer:
(i) To calculate the concentration of ion:
Case I (in the absence of HCl) :
Let the concentration of x M.
Then,
Taking we have
Case II (in the presence of HCl) :
In the presence of 0.1 M of , let be y M.
Also,
Now,
(ii) To calculate the concentration of :
Case I (in the absence of 0.1 M HCl) :
(From first ionization, case I)
Let be X.
Also, (From first ionization, case I)
Case II (in the presence of 0.1 M HCl) :
(From first ionization, case II)
(From HCl, case II)
Then,