Chemistry Class 11 NCERT Solutions: Chapter 7 Equilibrium Part 18

Chemistry Class 11 NCERT Solutions Chapter 7 Equilibrium Part 18

Q: 49. Calculate the pH of the following solutions:

(A) Equation Dissolved in water to give 2 litre of solution

(B) Equation Dissolved in water to give 500 mL of solution

(C) Equation Dissolved in water to give 200 mL of solution

(D) 1mL of 13.6 M HCl is diluted with water to give 1 litre of solution

Answer:

(A) For Equation dissolved in water to give 2 L of solution

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

(B) For 0.3 g of Equation dissolved in water to give 500 mL of solution:

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

(C) For 0.3 g of Equation dissolved in water to give 200 mL of solution:

Equation

Equation

Then, Equation

Equation

Equation

Equation

(D) For 1mL of 13.6 M HCl diluted with water to give 1 L of solution:

Equation

(Before dilution) (After dilution)

Equation

Equation

Equation

Equation

Equation

Equation

Q: 50. The degree of ionization of a Equation bromoacetic acid solution is 0.132. Calculate the pH of the solution and the Equation of bromoacetic acid

Answer:

Degree of ionization, Equation

Concentration, Equation

Thus, the concentration of Equation

Equation

Equation

Equation

Equation

Equation

Now,

Equation

Equation

Equation

Equation

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