Chemistry Class 11 NCERT Solutions: Chapter 7 Equilibrium Part 2

Download PDF of This Page (Size: 558K)

Chemistry Class 11 NCERT Solutions Chapter 7 Equilibrium Part 2

Q: 5. Find out the value of for each of the following equilibria from the value of

(i)

(ii)

Answer:

The relation between given as:

Image of Reaction of Kp and Kc for Equilibrium

Image of Reaction of Kp and Kc

Image of Reaction of Kp and Kc for Equilibrium

(A) Here,

Now,

(B) Here,

Now,

Q: 6. For the following equilibrium,

Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is for the reverse reaction?

Image of Bimolecular reactions for Equilibrium

Image of Bimolecular Reactions

Image of Bimolecular reactions for Equilibrium

Answer:

It is given that for the forward reaction is

Then, for the reverse reaction will be,

Q: 7. Explain why pure liquids and solids can be ignored while writing the equilibrium constant expression?

Image of Pure Liquids and Solids for Equilibrium

Image of Pure Liquids and Solids

Image of Pure Liquids and Solids for Equilibrium

Image of Liquid-Solid Equilibrium & Equilibrium

Image of Liquid-Solid Equilibrium

Image of Liquid-Solid Equilibrium & Equilibrium

Answer:

For a pure substance (both solids and liquids),

[Pure substance]=

Now, the molecular mass and density (at a particular temperature) of a pure substance is always fixed and is accounted for in the equilibrium constant. Therefore, the values of pure substances are not mentioned in the equilibrium constant expression.

Sign In