Chemistry Class 11 NCERT Solutions: Chapter 7 Equilibrium Part 2

Chemistry Class 11 NCERT Solutions Chapter 7 Equilibrium Part 2

Q: 5. Find out the value of Equation for each of the following equilibria from the value of Equation

(i) Equation

(ii) Equation

Answer:

The relation between Equation given as:

Image of Reaction of Kp and Kc for Equilibrium

Image of Reaction of Kp and Kc

Image of Reaction of Kp and Kc for Equilibrium

Equation

(A) Here,

Equation

Equation

Equation

Equation

Now,

Equation

Equation

Equation

Equation

(B) Here,

Equation

Equation

Equation

Equation

Now,

Equation

Equation

Equation

Equation

Q: 6. For the following equilibrium, Equation

Equation

Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is Equation for the reverse reaction?

Image of Bimolecular reactions for Equilibrium

Image of Bimolecular Reactions

Image of Bimolecular reactions for Equilibrium

Answer:

It is given that Equation for the forward reaction is Equation

Then, Equation for the reverse reaction will be,

Equation

Equation

Equation

Q: 7. Explain why pure liquids and solids can be ignored while writing the equilibrium constant expression?

Image of Pure Liquids and Solids for Equilibrium

Image of Pure Liquids and Solids

Image of Pure Liquids and Solids for Equilibrium

Image of Liquid-Solid Equilibrium & Equilibrium

Image of Liquid-Solid Equilibrium

Image of Liquid-Solid Equilibrium & Equilibrium

Answer:

For a pure substance (both solids and liquids),

[Pure substance]= Equation

Equation

Equation

Equation

Now, the molecular mass and density (at a particular temperature) of a pure substance is always fixed and is accounted for in the equilibrium constant. Therefore, the values of pure substances are not mentioned in the equilibrium constant expression.

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