Chemistry Class 11 NCERT Solutions: Chapter 7 Equilibrium Part 22

Q: 59. The ionization constant of Propionic acid is Equation . Calculate the degree of ionization of the acid in its 0.05M solution and also its pH. What will be its degree of ionization if the solution is 0.01M in HCl also?

Answer:

Let the degree of ionization of propionic acid be α.

Then, representing propionic acid as HA, we have

Equation

Equation

Equation

Equation

Then, Equation

Equation

In the presence of 0.1M of HCl, let Equation be the degree of ionization

Then, Equation

Equation

Equation

Equation

Equation

Equation

Q: 60. The pH of 0.1M solution of cyanic acid (HCNO) is 2.34. Calculate the ionization constant of the acid and its degree of ionization in the solution.

Answer:

Equation

Equation

Equation

Equation

Equation

Also,

Equation

Equation

Equation

Equation

Then,

Equation

Equation

Equation

Equation

Q: 61. The ionization constant of nitrous acid is Equation . Calculate the pH of 0.04 M sodium nitrite solution and also its degree of hydrolysis.

Answer:

Equation is the salt of a strong base (NaOH) and a weak acid Equation

Equation

Equation

Equation

Now, if x moles of the salt undergo hydrolysis, then the concentration of various species Present in the solution will be

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Equation

Therefore, degree of hydrolysis

Equation = Equation

Explore Solutions for Chemistry