Chemistry Class 11 NCERT Solutions: Chapter 7 Equilibrium Part 22 (For CBSE, ICSE, IAS, NET, NRA 2022)

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Q: 59. The ionization constant of Propionic acid is . Calculate the degree of ionization of the acid in its 0.05 M solution and its pH. What will be its degree of ionization if the solution is 0.01 M in HCl also?

Structure of Propanoic Acid

Answer:

Let the degree of ionization of propionic acid be α.

Then, representing propionic acid as HA, we have

Then,

In the presence of 0.1 M of HCl, let be the degree of ionization

Then,

Q: 60. The pH of 0.1 M solution of cyanic acid (HCNO) is 2.34. Calculate the ionization constant of the acid and its degree of ionization in the solution.

Answer:

Also,

Then,

Q: 61. The ionization constant of nitrous acid is . Calculate the pH of 0.04 M sodium nitrite solution and its degree of hydrolysis.

Answer:

is the salt of a strong base (NaOH) and a weak acid

Now, if x moles of the salt undergo hydrolysis, then the concentration of various species Present in the solution will be

Therefore, degree of hydrolysis

=

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