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Chemistry Class 11 NCERT Solutions: Chapter 7 Equilibrium Part 27
Q: 68. The solubility product constant of and are respectively. Calculate the ratio of the molarities of their saturated solutions.
Answer:
Let s be the solubility of
Then,
Let be the solubility of
Therefore, the ratio of the molarities of their saturated solution is
Q: 69. Equal volumes of 0.002 M solutions of sodium iodate and cupric chlorate are mixed. Will it lead to precipitation of copper iodate? (For cupric iodate )
Answer:
When equal volumes of sodium iodate and cupric chlorate solutions are mixed, then the molar concentrations of both solutions are reduced to half i.e.. , 0.001 M. Then,
Now, the solubility equilibrium for copper iodate can be written as:
Ionic product of copper iodate:
Since the ionic product is less than , precipitation will not occur.
Q: 70. The ionization constant of benzoic acid is and for silver benzoate is How many times is silver benzoate more soluble in a buffer of compared to its solubility in pure water?
Answer:
Since
Let the solubility of be x mol/L.
Then,
Thus, the solubility of silver benzoate in a pH 3.19 solution is 1.66 Γ 10 β 6 mol/L. Now, let the solubility of C6H5COOAg be xΥmol/L.
Then,
β΄
Hence, is approximately 3.317 times more soluble in a low pH solution.