Chemistry Class 11 NCERT Solutions: Chapter 7 Equilibrium Part 9

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Chemistry Class 11 NCERT Solutions Chapter 7 Equilibrium Part 9

Q: 24. Calculate a (∆G° and b) the equilibrium constant for the formation of and

Structure of of Magnitude of Kc

Structure of of Magnitude of Kc

Structure of of Magnitude of Kc

Answer:

(A) For the given reaction,

(B) We know that,

∆G° =RT log

Hence, the equilibrium constant for the given reaction

Q: 25. Does the number of moles of reaction products increase, decrease, or remain same when each of the following equilibria is subjected to a decrease in pressure by increasing the volume?

(A)

(B)

(C)

Answer:

(A) The number of moles of reaction products will increase. According to Le Chatelier’s principle, if pressure is decreased, then the equilibrium shifts in the direction in which the number of moles of gases is more. In the given reaction, the number of moles of gaseous products is more than that of gaseous reactants. Thus the reaction will proceed in the forward direction. As a result, the number of moles of reaction products will increase.

(B) The number of moles of reaction products will decrease

(C) The number of moles of reaction products remains the same

Q: 26. Which of the following reactions will get affected by increasing the pressure?

Also, mention whether change will cause the reaction to go into forward or backward direction.

(i)

(ii)

(iii)

(iv)

(v)

(vi)

Answer:

The reactions given in (i), (iii), (iv), (v), and (vi) will get affected by increasing the pressure.

The reaction given in (iv) will proceed in the forward direction because the number of moles of gaseous reactants is more than that of gaseous products.

The reactions given in (i), (iii), (v), and (vi) will shift in the backward direction because the number of moles of gaseous reactants is less than that of gaseous products.

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