Chemistry Class 11 NCERT Solutions: Chapter 8 Redox Reactions Part 1

Chemistry Class 11 NCERT Solutions Chapter 8 Redox Reactions Part 1

Q: 1. Assign oxidation numbers to the underlined elements in each of the following species

(A) Equation

(B) Equation

(C) Equation

(D) Equation

(E) Equation

(F) Equation

(G) Equation

(H) Equation

Answer:

(A) Equation

Let the oxidation number of P be x.

We know that,

Oxidation number of Equation

Oxidation number of Equation

Oxidation number of Equation

Equation

Then, we have

Equation

Equation

Equation

Hence, the oxidation number of P is +5

(B) Equation

Equation

Equation

Equation

Equation

Hence, the oxidation number of S is + 6.

(C) Equation

Equation

Then, we have

Equation

Equation

Equation

Equation

Hence, the oxidation number of P is + 5.

(D) Equation

Equation

Then, we have

Equation

Equation

Equation

Hence, the oxidation number of Mn is +6.

(E) Equation

Equation

Then, we have

Equation

Equation

Equation

Hence, the oxidation number of O is -1.

(F) Equation

Equation

Equation

Equation

Equation

Hence, the oxidation number of B is + 3.

(G) Equation

Equation

Then, we have

Equation

Equation

Equation

Equation

Hence, the oxidation number of S +6.

(H) Equation

Equation

Then, we have

Equation

Equation

Equation

Equation

Or,

We can ignore the water molecule, as it is a neutral molecule. Then, the sum of the oxidation numbers of all atoms of the water molecule may be taken as zero. Therefore, after ignoring the water molecule, we have

Equation

Equation

Equation

Equation

Hence, the oxidation number of S is + 6.

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