Chemistry Class 11 NCERT Solutions: Chapter 8 Redox Reactions Part 4

Chemistry Class 11 NCERT Solutions Chapter 8 Redox Reactions Part 4

Q: 5. Calculate the oxidation number of sulphur, chromium and nitrogen in Equation

Equation . Suggest structure of these compounds. Count for the fallacy.

Answer:

(i) Equation

Equation

Equation

However, the O.N. of S cannot be +8. S has six valence electrons. Therefore, the O.N. of

S cannot be more than +6.

The structure of Equation is shown as follows:

Now, Equation

Equation

Equation

Therefore, the O.N. of S is +6.

(ii) Equation

Equation

Equation

Equation

Here, there is no fallacy about the O.N. of Cr in Equation .

The structure of Equation is shown as follows:

Here, each of the two Cr atoms exhibits the O.N. of +6.

(iii) Equation

Equation

Equation

Equation

Here, there is no fallacy about the O.N. of N in Equation

The structure of Equation is shown as follows:

Image:

The N atom exhibits the O.N. of +5.

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