Chemistry Class 12 NCERT Solutions: Chapter 10 Haloalkanes and Haloarenes Part 14

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Text Solution:

Q: 1. Write structures of the following compounds:

(i) 2-Chloro-3-methylpentane

(ii) 1-Chloro-4-ethylcyclohexane

(iii) 4-tert. Butyl-3-iodoheptane

(iv) 1, 4-Dibromobut-2-ene

(v) 1-Bromo-4-sec. butyl-2-methylbenzene

Answer:

(i)

Q 1 i 2-Chloro-3-Methylpentane

Q 1 I 2-Chloro-3-Methylpentane

Q 1 i 2-Chloro-3-Methylpentane

2-Chloro-3-methylpentane

(ii)

Q 1 ii 1-Chloro-4-ethylcyclohexane

Q 1 Ii 1-Chloro-4-Ethylcyclohexane

Q 1 ii 1-Chloro-4-ethylcyclohexane

1-Chloro-4-ethylcyclohexane

(iii)

Q iii 4-Tert Butyl-3-Iodoheptane

Q Iii 4-Tert Butyl-3-Iodoheptane

Q iii 4-Tert Butyl-3-Iodoheptane

4-tert-Butyl-3-iodoheptane

(iv)

1, 4-Dibromobut-2-ene

(v)

Q ii v 1-Bromo-4-sec-butyl-2-methylbenzene

Q Ii v 1-Bromo-4-Sec-Butyl-2-Methylbenzene

Q ii v 1-Bromo-4-sec-butyl-2-methylbenzene

1-Bromo-4-sec-butyl-2-methylbenzene

Q: 2. Why is sulphuric acid not used during the reaction of alcohols with ?

Answer:

In the presence of sulphuric acid , KI produces

Since is an oxidizing agent, it oxidizes (produced in the reaction to )

As a result, the reaction between alcohol and to produce alkyl iodide cannot occur. Therefore, sulphuric acid is not used during the reaction of alcohols with . Instead, a non-oxidizing acid such as is used.

Q: 3. Write structures of different dihalogen derivatives of propane.

Answer:

There are four different dihalogen derivatives of propane. The structures of these derivatives are shown below.

(i)

1, 1-Dibromopropane

(ii)

2, 2-Dibromopropane

(iii)

1, 2-Dibromopropane

(iv)

1, 3-Dibromopropane