Chemistry Class 12 NCERT Solutions: Chapter 15 Polymers Part 4 (For CBSE, ICSE, IAS, NET, NRA 2022)

Get top class preparation for CBSE/Class-12 right from your home: get questions, notes, tests, video lectures and more- for all subjects of CBSE/Class-12.

Q: 1. What are polymers?

Answer:

Polymers are high molecular mass macromolecules, which consist of repeating structural units derived from monomers. Polymers have a high molecular mass . In a polymer, various monomer units are joined by strong covalent bonds. These polymers can be natural as well as synthetic. Polythene, rubber, and nylon 6,6 are examples of polymers.

Q: 2. How are polymers classified on the basis of structure?

Answer:

Polymers are classified on the basis of structure as follows:

1. Linear Polymers:

These polymers are formed of long straight chains. They can be depicted as:

Q_2_1_Structure of Linear Polymers

For e. g. , high density polythene (HDP) , polyvinyl chloride, etc.

2. Branched chain polymers:

These polymers are basically linear chain polymers with some branches. These polymers are represented as:

Q_2_2_Structure of Branched Chain Polymers

For e. g. , low density polythene (LDP) , amylopectin, etc.

3. Cross-linked or Network polymers:

These polymers have many cross-linking bonds that give rise to a network-like structure. These polymers contain bi-functional and tri-functional monomers and strong covalent bonds between various linear polymer chains. Examples of such polymers include bakelite and melmac.

Q_2_3_Structure of Cross-Linked or Network Polymers
Q_2_Polymer Classification

Q: 3. Write the names of monomers of the following polymers:

(i)

(ii)

(iii)

Answer:

(i) Hexamethylenediamine and adipic acid

(ii)

Q_3_Structure of Caprolactam

(iii) Tetrafluoroethylene

Q: 4. Classify the following as addition and condensation polymers: Terylene, Bakelite, Polyvinyl chloride, Polythene.

Answer:

Addition polymers:

Polyvinyl chloride, polythene

Condensation polymers:

Terylene, bakelite

Q: 5. Explain the difference between Buna-N and Buna-S.

Answer:

Buna − N is a copolymer of 1,3 − butadiene and acrylonitrile.

Buna − S is a copolymer of 1,3 − butadiene and styrene.

Q: 6. Arrange the following polymers in increasing order of their intermolecular forces.

(i) Nylon 6,6, Buna-S, Polythene.

(ii) Nylon 6, Neoprene, Polyvinyl chloride.

Answer:

Different types of polymers have different intermolecular forces of attraction. Elastomers or rubbers have the weakest while fibres have the strongest intermolecular forces of attraction. Plastics have intermediate intermolecular forces of attraction. Hence, the increasing order of the intermolecular forces of the given polymers is as follows:

(i) Buna − S < polythene < Nylon 6,6

(ii) Neoprene < polyvinyl chloride < Nylon 6

Developed by: