Chemistry Class 12 NCERT Solutions: Chapter 2 Solutions Part 2

Q: 5. Calculate

(A) Molality

(B) Molarity and

(C) Mole fraction

Of KI if the density of 20% (mass/mass) aqueous KI is Equation .

Ans:

(A) Molar mass of Equation

Equation (mass/mass) aqueous solution of Equation means Equation is present in 100 g of solution. That is,

20 g of KI is present in Equation of water Equation of water

Therefore, molality of the solution Equation

Equation

Equation

Equation (Approximately)

(B) It is given that the density of the solution Equation

Equation

Equation

Equation

Equation

Therefore, molarity of the solution Equation

Equation

(C) Equation

Moles of water Equation

Therefore, mole fraction of Equation

Equation

Equation

Q: 6. Equation , a toxic gas with rotten egg like smell, is used for the qualitative analysis. If the solubility of Equation in water at Equation P is Equation m, calculate Henry's law constant.

Ans:

It is given that the solubility of Equation in water at STP is Equation i.e., Equation of Equation is dissolved in Equation of water. Moles of water Equation

Equation

Equation Mole fraction of Equation

Equation

Equation

At STP, pressure Equation

According to Henry’s law

Equation

Equation

Equation

Equation

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