Chemistry Class 12 NCERT Solutions: Chapter 4 ChemicalKinetic Part 11
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Q: 22. The rate constant for the decomposition of at various temperatures is given below:
 0  20  40  60  80 






Draw a graph between ln and and calculate the values of A and .
Predict the rate constant at .
Answer:
From the given data, we obtain
 0  20  40  60  80 
 273  293  313  333  353 


















Slope of the line,
According to Arrhenius equation,
Slope
Again,
When
Then,
Therefore,
When
Then,
Therefore,
Again, when
Therefore,
Q: 23. The rate constant for the decomposition of hydrocarbons is . If the energy of activation is , what will be the value of preexponential factor.
Answer:
According to the Arrhenius equation,
Therefore,