Chemistry Class 12 NCERT Solutions: Chapter 9 Coordination Compounds Part 14

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Q: 8. Explain is an inner orbital complex whereas complex.

Q_8_The Inner Orbital Complex
Q_8_The Inner Orbital Complex

Oxidation state of cobalt

Oxidation state of

Electronic configuration of cobalt

Electronic configuration of nickel

Q 8 1 NH3Being A Strong Field Ligang Causes The Pairing

Q 8 1 NH3Being a Strong Field Ligang Causes the Pairing

Q 8 1 NH3Being A Strong Field Ligang Causes The Pairing

being a strong field ligand causes the

pairing. Therefore, can undergo

hybridization.

Q 8 2 Ni Can Undergo D2 sp3 Hybridization

Q 8 2 Ni Can Undergo D2 sp3 Hybridization

Q 8 2 Ni Can Undergo D2 sp3 Hybridization

Hence, it is an inner orbital complex.

Q 8 3 The Pairing, Then Only One 3

Q 8 3 the Pairing, Then Only One 3

Q 8 3 The Pairing, Then Only One 3

If causes the pairing, then only one

orbital is empty. Thus, it cannot undergo hybridization. Therefore, it undergoes hybridization.

Q 8 4 The Undergoes sp3 d2 Hybridization

Q 8 4 the Undergoes sp3 d2 Hybridization

Q 8 4 The Undergoes sp3 d2 Hybridization

Hence, it forms an outer orbital complex.

Q: 9. Predict the number of unpaired electrons in the square planar ion.

Answer

In this complex, is in the state. It forms a square planar structure. This means that it undergoes hybridization. Now, the electronic configuration of .

Q 9 The Electronic Configuration

Q 10 the Electronic Configuration

Q 9 The Electronic Configuration

being a strong field ligand causes the pairing of unpaired electrons. Hence, there are no unpaired electrons in

Q: 10. The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacyanoion contains only one unpaired electron. Explain using Crystal Field Theory.

Answer:

Q_10_The Hexaquo Manganese(II) Ion Contains Five Unpaired Electrons
Q_10_The Hexaquo Manganese(II) ion Contains Five Unpaired Electrons

Mn is in the oxidation state

Mn is in the oxidation state

The electronic configuration is .

The electronic configuration is .

The crystal field is octahedral. Water is a weak field ligand. Therefore, the arrangement of the electrons in is .

The crystal field is octahedral. Cyanide i

a strong field ligand. Therefore, the arrangement of the electrons i is .

Hence, hexaquo manganese (II) ion has five unpaired electrons

while hexacyanoion ion has only one unpaired electron.

Q: 11. Calculate the overall complex dissociation equilibrium constant for the ion, given that for this complex is .

Answer:

The overall complex dissociation equilibrium constant is the reciprocal of the overall stability constant, .