NCERT Class 9 Solutions: Circles (Chapter 10) Exercise 10.6 – Part 4

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Angle ABC bisected by line segment BE

Be is Angle Bisector of Angle ABC

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Angle Bisector. A line that splits an angle into two equal angles. ("Bisect" means to divide into two equal parts.)

Q-7 PQ and RS are chords of a circle which bisect each other. Prove that

  1. PQ and RS are diameters

  2. PRQS is a rectangle.


PQ and RS Bisect Each Other at Point O

Solution (i): To prove PQ and RS are diameters


  • PQ and RS are two chords of a circle which intersect at O.

  • They bisects each other at O


Join PS, SQ, QR and RP.


  • (O is the mid-point of SR)

  • (Vertically opposite angles)

  • (O is the mid-point of SQ)

  • Therefore, by Side-Angle-Side criterion of congruence.

  • Therefore,

  • Since segment PQ and SR are equal, corresponding arcs in the circle are also equal, therefore ………..equation (1)

  • Similarly, in and

    • ……….equation (2)

  • From equation (1) and (2)

Therefore PQ divides the circle into two parts

Therefore PQ is a diameter.

Similarly, we can prove that PR is a diameter.

Solution (ii): To prove PRQS is a rectangle.

(Proved above), therefore,

With two lines PR and SQ intersected by transversal SR the pair of interior opposite angles are equal, therefore,

Similarly, and

Since and , Therefore PRQS is a cyclic parallelogram

Also, ……….equation (3) (because opposite angle of a parallelogram are equal)

Since PRQS is a cyclic quadrilateral

Therefore pair of opposite angles are supplementary, therefore ……….equation (4)

From equation (3) and (4)

  • ()

Since opposite angles of parallelogram PRQS are each, therefore, PRQS is a rectangle.

Q-8 Bisectors of angle P, Q and R of a triangle PQR intersect its circumcircle at C, A and B respectively, Prove that the angles of the triangle CAB are


Bisectors of Triangle PQR Intersect at Its Circumcircle

  • Since are angles in same segment of circle (AP), therefore . Similarly, . Therefore equation above can be written as (Since QA and RB are angle bisectors of and .

  • Therefore,


  • and


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