# NCERT Class 9 Solutions: Surface Areas and Volumes (Chapter 13) Exercise 13.3 – Part 2 (For CBSE, ICSE, IAS, NET, NRA 2022)

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Slant height l or s =

Q-4 A conical tent is high and the radius of its base is . Find

- Slant height of the tent.
- Cost of the canvas required to make the tent, if the cost of canvas is

Solution (I) :

- Radius of the base (r)
- Height of the conical tent (h)

Therefore, the slant height of the cone is .

Solution (II) :

Canvas required to make the conical tent is the curved or lateral surface of the cone. Note that the tent does not have a base. Also, cost of canvas

Area of canvas = ()

Therefore, cost of canvas = ₹

5. What length of tarpaulin wide will be required to make conical tent of height and base radius ? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately (Use ) . Solution:

- Radius of the base (r)
- Height of the conical tent (h)

Now, l is the slant height of the cone

Curved surface area of conical tent =

We know that breadth of tarpaulin . Let, is length of tarpaulin sheet required of which we know from the problem that will be wasted in cutting. So, the actual length used will be . Now area of this sheet with length and breadth of must match the lateral surface area of the sheet,

That is,