# NCERT Class 9 Solutions: Surface Areas and Volumes (Chapter 13) Exercise 13.3 – Part 3 (For CBSE, ICSE, IAS, NET, NRA 2022)

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Q-6 The slant height and base diameter of a conical tomb are and respectively. Find the cost of white-washing its curved surface at the rate of per Solution:

We know,

- Base diameter =
- Radius (r)
- Slant height of tomb (l)

Therefore, curved surface area =

Rate of white- washing 100 m^{2}

Rate of white- washing 1 m^{2}

Therefore, total cost of white-washing the tomb with area

Q-7 A joker՚s cap is in the form of a right circular cone of base radius and height . Find the area of the sheet required to make such caps. Solution:

- The cone radius (r)
- The cone height (h)

Now, l be the slant height

Sheet required for one cap = Curved surface of the cone

Sheet required for

Q-8 A bus stop is barricaded from the remaining part of the road, by using hollow cones made of recycled cardboard. Each cone has a base diameter of and height 1 m. If the outer side of each of the cones is to be painted and the cost of painting is , what will be the cost of painting all these cones? (Use and take )

Solution:

We are given,

- Radius of the cone (r)
- Height of the cone (h)

Now, the slant height of a cone is given by

We know that, rate of painting

Curved surface area of 1 cone =

Therefore, curved surface of such 50 cones =

Finally, cost of painting all these cones is (since, the cost of painting is )