Q-7 The runs scored by two teams A and B on the first 60 balls in a cricket match are given below:
Runs scored by two teams in cricket matchRuns scored by two teams A and B in 60 balls of cricket match
Number of balls
Teams A
Team B
2
5
1
6
8
2
9
10
4
5
5
6
6
3
10
4
6
8
2
10
Represent the table data of both the teams on the same graph by frequency polygons.
[Hint: First make the class intervals continuous.]
Solution:
Convert to continuous frequency distribution:
Difference between lower limit of class and upper limit of preceding class:
Hence, added to each upper class limit and subtract from the lower class limits.
Class marks
Obtain distribution is given as under:
Obtain continuous frequency distributionObtain continuous frequency distribution
Number of balls
Class marks
Team A
Team B
3.5
2
5
9.5
1
6
15.5
8
2
21.5
9
10
27.5
4
5
33.5
4
5
39.5
6
3
45.5
10
4
51.5
6
8
57.5
2
10
Class mark on x-axis and number of balls on y-axis
Drawn the graph:
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Q-8 A random survey of the number of children of various age groups playing in park was found as follows:
Draw a histogram to represent the data of tableDraw a histogram to represent the data of table
Age (in years)
Number of children
5
3
6
12
9
10
4
Draw a histogram to represent the data above.
Solution:
As given frequency data in class size are different.
So, we calculate adjusted frequency for each class using formula:
Adjusted frequency
Here, minimum class size
Find the adjusted frequency to draw histogramFind the adjusted frequency to draw histogram
Age (In year)
Frequency (number of children)
Width of classes
Adjusted Frequency
5
1
3
1
6
2
12
2
9
3
10
5
4
2
In below chart age of children on x-axis
Proportion of children per 1 year interval on y-axis
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