# NCERT Class 9 Solutions: Statistics (Chapter 14) Exercise 14.3-Part 3

Q-7 The runs scored by two teams A and B on the first 60 balls in a cricket match are given below:

 Number of balls Teams A Team B Equation 2 5 Equation 1 6 Equation 8 2 Equation 9 10 Equation 4 5 Equation 5 6 Equation 6 3 Equation 10 4 Equation 6 8 Equation 2 10

Represent the table data of both the teams on the same graph by frequency polygons.

[Hint: First make the class intervals continuous.]

Solution:

Convert to continuous frequency distribution:

Difference between lower limit of class and upper limit of preceding class:

Hence, added to each upper class limit and subtract from the lower class limits.

Class marks

Obtain distribution is given as under:

 Number of balls Class marks Team A Team B Equation 3.5 2 5 Equation 9.5 1 6 Equation 15.5 8 2 Equation 21.5 9 10 Equation 27.5 4 5 Equation 33.5 4 5 Equation 39.5 6 3 Equation 45.5 10 4 Equation 51.5 6 8 Equation 57.5 2 10

Class mark on x-axis and number of balls on y-axis

Drawn the graph:

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Q-8 A random survey of the number of children of various age groups playing in park was found as follows:

 Age (in years) Number of children Equation 5 Equation 3 Equation 6 Equation 12 Equation 9 Equation 10 Equation 4

Draw a histogram to represent the data above.

Solution:

As given frequency data in class size are different.

So, we calculate adjusted frequency for each class using formula:

Adjusted frequency

Here, minimum class size

 Age (In year) Frequency (number of children) Width of classes Adjusted Frequency Equation 5 1 Equation Equation 3 1 Equation Equation 6 2 Equation Equation 12 2 Equation Equation 9 3 Equation Equation 10 5 Equation Equation 4 2 Equation

In below chart age of children on x-axis

Proportion of children per 1 year interval on y-axis

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