NCERT Class 9 Solutions: Polynomials (Chapter 2) Exercise 2.2 – Part 1

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Q-1 Find the value of the polynomial 5x4x2+3 at

  1. x=0

  2. x=1

  3. x=2

Evaluating a polynomial at a particular value

Evaluating the Value of a Polynomial

Evaluating a polynomial at a particular value

Solution:

  1. p(x)=5x4x2+3

    p(0)=5(0)4(0)2+3

    p(0)=3

  2. p(x)=5x4x2+3

    p(1)=5(1)4(1)2+3

    p(1)=54+3

    p(1)=6

  3. p(x)=5x4x2+3

    p(2)=5(2)4(2)2+3

    p(2)=1016+3

    p(2)=3

Q-2 Find p(0),p(1)andp(2) for each of the following polynomials:

  1. p(y)=y2y+1

  2. p(t)=2+t+2t2t3

  3. p(x)=x3

  4. p(x)=(x1)(x+1)

Solution:

  1. p(y)=y2y+1

    p(0)=(0)20+1=1

    p(1)=(1)21+1=1

    p(2)=(2)22+1=42+1=2+1=3

  2. p(t)=2+t+2t2t3

    p(0)=2+0+2(0)2(0)3=2

    p(1)=2+1+2(1)2(1)3=2+1+21=4

    p(2)=2+2+2(2)2(2)3=2+2+88=4

  3. p(x)=x3

    p(0)=(0)3=0

    p(1)=(1)3=1

    p(2)=(2)3=8

  4. p(x)=(x1)(x+1)

    p(0)=(01)(0+1)=1×1=1

    p(1)=(11)(1+1)=0×2=0

    p(2)=(21)(2+1)=1×3=3

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