# NCERT Class 9 Solutions: Polynomials (Chapter 2) Exercise 2.4 – Part 1 (For CBSE, ICSE, IAS, NET, NRA 2022)

Glide to success with Doorsteptutor material for ISAT : Get full length tests using official NTA interface: all topics with exact weightage, real exam experience, detailed analytics, comparison and rankings, & questions with full solutions.

**Q-1** Determine which of the following polynomials has a factor:

Solution:

If is a factor of a polynomial , then we can write, Since zero multiplied by any number is zero. Therefore, this polynomial would become zero for all the values of *x* where either becomes zero or becomes zero. We don՚t know anything about g (x) but we know that becomes zero for . Therefore, Therefore, if x + 1 is a factor of p (x) , p (x) must become zero at x =-1. For each polynomial above we would test its value at x =-1. If it comes out to be zero (x + 1) is a factor of that polynomial.

- Let

Is a factor of polynomial

- Let

Is not a factor of polynomial

- Let

Is not a factor of polynomial

- Let

Is not a factor of polynomial

**Q-2** Use the Factor Theorem to determine whether is a factor of in each of the following cases:

Solution:

Zero of is .

If is a factor of then *p* must also have a zero at -1, i.e..

Is a factor of polynomial .

Zero of is .

If is a factor of then *p* must also have a zero at -2, i.e..

Is not a factor of polynomial .

Zero of is .

If is a factor of then *p* must also have a zero at 3, i.e..

Is a factor of polynomial .