NCERT Class 9 Solutions: Linear Equation in Two Variable (Chapter 4) Exercise 4.3 – Part-3 (For CBSE, ICSE, IAS, NET, NRA 2022)

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Q-4 The taxi fare in a city is as follows: For the first kilometer, the fare is ₹ 8 and for the subsequent distance it is ₹ 5 per kilometer. Taking the distance covered as x km and total fares as ₹ y, write a linear equation for this information, and draw its graph.

Solution:

Given,

Taxi fare for subsequent distance ₹ 5

Let,

  • Total distance covered
  • Total fare

According to problem,

  • Taxi fare for first kilometer ₹ 8
  • If the total distance is x, fare for rest of the kilometer (at the rate of ₹ 5 per km)
  • Since the fare for first kilometer = ₹ 8, so, the total fare

Hence, is the required linear equation

Drawing the Graph

We can draw the graph by finding two points on this equation and drawing a line joining those points.

The equation is

… equation (1)

Now, putting the value in equation (1)

So the solution is this is first point (the y intercept)

Putting the value in equation (1)

. So the solution is this is the second point

Graph for Equation Y = 5x + 3