NCERT Class 9 Solutions: Linear Equation In Two Variable (Chapter 4) Exercise 4.3 – Part 5
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Graph of linear equation
Q6 The work done by a body on application of a constant force is directly proportional to the distance travelled by the body. Express this in the form of an equation in two variables and draw the graph of the same by taking the constant force is 5 units. Read from the graph the work done when the distance traveled by the body is:

2 units

0 units
Solution:
Let units be the distance traveled by the body and units be the work done by constant force. . The equality is , where F is the force. So if F = 5 than, according to question,
To draw the graph we find a few points on this equation.

Putting the value in the equation
So the solution is

Putting the value in the equation
So the solution is

Putting the value in the equation
. So the solution is

When units (distance), we read the graph above and find the value of y when the value of x is 2. The red line tell us where on our graph the xcoordinate is 2. Another line from that point to y axis tells us the corresponding value of y (green line). The corresponding ycoordinate is 10. This is the corresponding work done.

When units (distance), we know the corresponding ycoordinate on our workforce graph is y = 0 (our line passes through 0, 0).
Q7 Yamini and Fatima, two students of class IX of a school, together contributed Rs. 100 towards the Prime Minister’s Relief Fund, to help the earthquake victims. Write a linear equation which this data satisfies. (You may take their contributions as Rs. and Rs. ). Draw the graph of the same.
Solution:
The idea is that we know their total contribution to be 100 but not individual contribution. Therefore, if the contribution of Yamini is and that of Fatima is . Then, . We will again draw the graph by finding a few points.

Putting the value
. So one point is

Putting the value
. So another point is

Putting the value
Or,
. So the point is
See how all coordinates of all points on this graph add to 100!