NCERT Class 9 Solutions: Line and Angles (Chapter 6) Exercise 6.1 – Part 3

Equality of Corresponding angles

Equality of Corresponding Angles

Equality of Corresponding angles

Q-5 In the figure, POQ is a line. Ray OR is perpendicular to line PQ. OS is another ray lying between rays OP and OR. Prove that Equation

Angle α Angle α: Angle between Q, O, Q' Angle α Angle α: Angle between Q, O, Q' Vector u Vector u: Vector[O, B] Vector u Vector u: Vector[O, B] Vector v Vector v: Vector[O, C] Vector v Vector v: Vector[O, C] Vector w Vector w: Vector[O, D] Vector w Vector w: Vector[O, D] Vector a Vector a: Vector[O, E] Vector a Vector a: Vector[O, E] Point O O = (0.32, 1.14) Point O O = (0.32, 1.14) Point O O = (0.32, 1.14) Point S Point S: Point on a Point S Point S: Point on a Point S Point S: Point on a Point R Point R: Point on w Point R Point R: Point on w Point R Point R: Point on w Point Q Point Q: Point on u Point Q Point Q: Point on u Point Q Point Q: Point on u Point P Point P: Point on v Point P Point P: Point on v Point P Point P: Point on v

Point of O, P, Q, R, S and Angle ROQ Is 90 Degree

Point of O, P, Q, R, S and POQ is a line. Ray OR is perpendicular to line PQ. OS is another ray lying between rays OP and OR.

Solution,

Give point O, P, Q, R, S and POQ is a line. Ray OR is perpendicular to line PQ. OS is another ray lying between rays OP and OR.

Prove,

Equation

Equation, Equation (Perpendicular)

Equation ……….equation (1) Equation ………..equation (2)

Subtracting (1) from (2) Equation

Equation

Q-6 It is given that Equation and XY is produced to point P. Draw a figure from the given information. If ray YQ bisects Equation , find Equation and reflex Equation

Solution:

Give point of P,Q,X,Y,Z and Equation

YQ bisects Equation

Angle α Angle α: Angle between Z, Y, X Angle α Angle α: Angle between Z, Y, X Angle α Angle α: Angle between Z, Y, X Segment f Segment f: Segment [X, P] Segment g Segment g: Segment [Y, Q] Segment h Segment h: Segment [Y, Z] Point X X = (-2.22, 1.32) Point X X = (-2.22, 1.32) Point X X = (-2.22, 1.32) Point P P = (3.46, 1.32) Point P P = (3.46, 1.32) Point P P = (3.46, 1.32) Point Y Point Y: Point on f Point Y Point Y: Point on f Point Y Point Y: Point on f Point Q Q = (2.66, 4.14) Point Q Q = (2.66, 4.14) Point Q Q = (2.66, 4.14) Point Z Z = (-2.06, 4.06) Point Z Z = (-2.06, 4.06) Point Z Z = (-2.06, 4.06)

Point of P,Q,X,Y,Z and Angle XYZ 64 Degree

Point of P, Q, X, Y, Z and XYZ 64 degree also XY is produced to point P

Equation (Linear Pair) Equation Equation

Also,

Equation Equation (YQ bisects Equation )

Equation Equation Equation Equation Equation

Now, Equation Equation Equation

Equation

Also, reflex Equation Equation

Equation

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