NCERT Class 9 Solutions: Areas of Parallelograms and Triangles (Chapter 9) Exercise 9.2 – Part 1

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The area of a parallelogram it is equal to the product of the base the height,A=bh

The Area of a Parallelogram a=Bh

The area of a parallelogram it is equal to the product of the base the height,A=bh

Q-1 In the figure, ABCD is a parallelogram, and .If , and , find .

Parallelomgram ABCD

Parallelomgram ABCD also AE⊥DC andCF⊥AD.

Solution:

Given,

  • ABCD is a parallelogram, and

  • Also (opposite side of a parallelogram)

  • and

Now,

  • ( )

  • (

Q-2 If E, F, G and H are respectively the mid-points of the sides of a parallelogram ABCD, show that ar

Solution:

Parallelogram ABCD

Parallelogram ABCD also E,F,G,H are respectivly the mid-point of the side

  • Given, E, F, G and H are respectively the mid-point of the sides of a parallelogram ABCD

  • To prove,

  • Construction, H and F are joined.

Proof,

  • and (opposite sides of a parallelogram) so

  • Also, and therefore and (H and F are mid points) Thus, ABFH and HFCD are parallelograms.

  • Now, And parallelogram ABFH lie on the same base FH and between the same parallel lines AB and HF.

  • So, area of ……….equation (1) (this is because area of triangle is and area of parallelogram is and the triangle and parallelogram share same base and height),

  • Similarly, area of ……..equation (2)

Adding equation (1) and (2)

  • Area of area of

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