# Physics Class 12 NCERT Solutions: Chapter 1 Electric Charges and Fields Part 10 (For CBSE, ICSE, IAS, NET, NRA 2022)

Glide to success with Doorsteptutor material for CBSE/Class-12 Business-Studies: fully solved questions with step-by-step explanation- practice your way to success.

Q: 30. Obtain the formula for the electric field due to a long thin wire of uniform linear charge density without using Gauss՚s law. [Hint: Use Coulomb՚s law directly and evaluate the necessary integral.]

Answer:

Take a long thin wire XY (as shown in the figure) of uniform linear charge density .

Consider a point A at a perpendicular distance/from the mid-point O of the wire, as shown in the following figure.

Let be the electric field at point A due to the wire, XY.

Consider a small length element dx on the wire section with

Let q be the charge on this piece.

Electric field due to the piece,

However,

The electric field is resolved into two rectangular components. is the perpendicular component and is the parallel component. When the whole wire is considered, the component is cancelled.

Only the perpendicular component affects point A.

Hence, effective electric field at point A due to the element is .

,

On differentiating equation (2) , we obtain

From equation (2) ,

Putting equations (3) and (4) in equation (1) , we obtain

The wire is so long that tends from to .

By integrating equation (5) , we obtain the value of field as,

Therefore, the electric field due to long wire is .