Physics Class 12 NCERT Solutions: Chapter 13 Nuclei Part 2 (For CBSE, ICSE, IAS, NET, NRA 2023)
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Q: 4. Obtain the binding energy of the nuclei and in units of from the following data:
Answer:
Atomic mass of
Nucleus has protons and neutrons
Hence, the mass defect of the nucleus,
Where,
But
The binding energy of this nucleus is given as:
Where,
Speed of light
Average binding energy per nucleon
Atomic mass of
Nucleus has protons and neutrons.
Hence, the mass defect of this nucleus is given as:
Where,
Mass of a proton,
Mass of a neutron,
But
Hence, the binding energy of this nucleus is given as:
Average binding energy per nucleon
Q: 5. A given coin has a mass of . Calculate the nuclear energy that would be required to separate all the neutrons and protons from each other. For simplicity assume that the coin is entirely made of atoms .
Answer:
Mass of a copper coin,
Atomic mass of atom,
The total number of atoms in the coin
Where,
Avogadro՚s number
Mass number
Nucleus has protons and neutrons
∴ Mass defect of this nucleus,
Where,
Mass of a proton,
Mass of a neutron,
Mass defect of all the atoms present in the coin,
But
Hence, the binding energy of the nuclei of the coin is given as:
But
This much energy is required to separate all the neutrons and protons from the given coin.