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Physics Class 12 NCERT Solutions: Chapter 9 Ray Optics and Optical Instruments Part 5
Q: 11. A compound microscope consists of an objective lens of focal length and an eyepiece of focal length separated by a distance of . How far from the objective should an object be placed in order to obtain the final image at (a) the least distance of distinct vision , and (b) at infinity? What is the magnifying power of the microscope in each case?
Answer:
Focal length of the objective lens,
Focal length of the eyepiece,
Distance between the objective lens and the eyepiece,
(A) Least distance of distinct vision,
β΄ Image distance for the eyepiece,
Object distance for the eyepiece
According to the lens formula, we have the relation:
Image distance for the objective lens,
Object distance for the objective lens
According to the lens formula, we have the relation:
Magnitude of the object distance,
The magnifying power of a compound microscope is given by the relation:
Hence, the magnifying power of the microscope is .
(B) The final image is formed at infinity.
β΄ Image distance for the eyepiece,
Object distance for the eyepiece
According to the lens formula, we have the relation:
Image distance for the objective lens,
Object distance for the objective lens
According to the lens formula, we have the relation:
Magnitude of the object distance,
The magnifying power of a compound microscope is given by the relation:
Hence, the magnifying power of the microscope is .